| Tarjeta |
Solución |
| \frac{(x-3)}{12}=\frac{3x-9}{10} |
3 |
| 3(x+5)-4(x+1)=10 |
1 |
| \frac{x}{5} + \frac{3x}{2} =\frac{17}{2} |
5 |
| 3(x-2)=2(3x-6) |
2 |
| 2(x-5)-x=3(1-x)+11 |
6 |
| 4(-x-3)=2(x+3) |
-3 |
| 1+\frac{x+4}{3}=x-5 |
11 |
| \frac{3x}{9}+\frac{x}{5}=x-7 |
15 |
| \frac{2x-5}{3}+x=\frac{-5+x}{2}-5 |
-5 |
| 5(x-10)+2(x+10)-4x=0 |
10 |
| 2(x-13)+2x-25=2(x-11)-3 |
13 |
| 2(x-8)+3(9-x)=3(x-7)-4 |
9 |
| x+1-3(2-x)=-21 |
-4 |
| \frac{x}{2}-\frac{x}{3}=\frac{x}{4} |
0 |
| \frac{2x}{7}+1=\frac{x+1}{3} |
14 |
| 3(x-1)-2(2x-7)=4x-9 |
4 |
| 3+\frac{x}{2}=x-\frac{1}{2} |
7 |
| \frac{x+2}{5}+x+6=-x+2 |
-2 |
| \frac{x+3}{4}=x+1+\frac{x+1}{2}+\frac{x+4}{6} |
-1 |
| -(x+4)+2(x-8)=-(x-4) |
12 |
| 4(x-7)-2(x-4)=12-2x |
8 |
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